Subnetting
During this unit you will need to earn 525 points to receive an A. This
sheet will serve as your grading sheet. Everything, with the exception of the
reading assignments and quizzes, is due after the unit test. Attach this sheet
to the top of your packet of work and have the teacher check it off.
This is an “on your
own” unit and the entire unit must be completed correctly for any credit. If
you do not do all three sections, and all of the items in each section, you
will receive an incomplete.
|
Option |
Points |
Teacher Initials |
What is an IP Address (do this first
before the lecture)
|
30 |
|
|
IP Address Quiz (examview) |
30 |
|
|
Binary Practice |
20 |
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|
Custom Subnetting |
100 |
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Custom Subnet Quiz |
100 |
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|
_______ |
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Total for Section C |
____/180 |
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Option |
Points |
Teacher Initials |
|
Networking News: Go online and find an
article, new story, or white paper that relates to IP addresses, custom
subnetting, supernetting, VLSM, or CIDR.
8 Print the
article (10) 8 Read the article
and write a two paragraph summary of what it says (20) 8 Write a
paragraph explaining how a network administrator might use the information in
this article (20) 8 Locate two other
related websites and print them (20) |
_____/70 |
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Total for Section B |
____/70 |
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Option |
Points |
Teacher Initials |
|
8 Job One: Converting Binary Numbers |
____/20 |
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8 Job Two: Defining a Subnet for your network o Figure out the custom subnets (show me) (20) o Set up appropriate subnets on three-five computers (each student do one) (20) |
____/40 |
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8 Job Three: Download IP Calculator o Download and install Calculator (5) o Complete problems (10) |
____/15 |
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Total for Section A |
_____/75
|
|
Lab Test ScoreWhen you complete the test have me come and write your test score in this box. |
_____/100 |
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Test ScoreWhen you complete the test have me come and write your test score in this box. |
_____/100 |
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Total Points for UnitAdd up your points and write them in this box. I will verify your score and put it into the gradebook. |
_________/525 |
|

Unit Grade |
|
|
Current Class Grade |
|
______________________________________________________
Parent Signature
What
is an IP Address?
Go to the website: www.howstuffworks.com/question549.htm
Read and answer the questions below.
Multiple
Choice
Identify the choice that best completes the statement or
answers the question.
____ 1. To make it easier on humans, IP addresses are
typically written in what formation?
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a. |
octal |
c. |
binary |
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b. |
dotted decimal |
d. |
hexadecimal |
____ 2. The four numbers in an IP address are called:
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a. |
quartets |
c. |
octets |
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b. |
quintets |
d. |
decimal notations |
____ 3. The value 0.0.0.0 is reserved for the
_____ _____.
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a. |
default network |
c. |
multicast network |
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b. |
broadcast network |
d. |
local host |
____ 4. The value 255.255.255.255 is reserved for the
_____ _____.
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a. |
default network |
c. |
multicast network |
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b. |
broadcast network |
d. |
local host |
____ 5. The class D IP addresses are reserved for the
_____
|
a. |
default network |
c. |
multicast |
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b. |
broadcast network |
d. |
local host |
____ 6. The most common IP address scheme used today
is:
|
a. |
IPV6 |
c. |
IPV4 |
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b. |
IPNG |
d. |
CIDR |
Multiple Response
Identify one or more choices that best complete the
statement or answer the question.
____ 7. Octets are split into two sections:
|
a. |
Net or network |
c. |
Router |
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b. |
Host |
d. |
Frame |
Click the link at the bottom of
the page that says: 3COM Understanding IP Addressing. Answer the following.
____ 8. The new addressing scheme, known as ____ or
____, is the long-term solution to the limitations of IPV4.
|
a. |
CIDR |
c. |
IPv6 |
|
b. |
IPV9 |
d. |
IPng |
____ 9. Which of the following are workarounds that
are used to address the problem of running out of addresses in IPv4?
|
a. |
CIDR |
c. |
VLSM |
|
b. |
IPV9 |
d. |
Subnetting |
10. The first four bits of a class D address are:
11. The default subnet mask for a class A address
is:
12. The default subnet mask for a class B address is:
13. The default subnet mask for a class C address
is:
Completion
14. 192.168.1.2 is a class ______ address.
15. 13.254.6.21 is a class ____ address.
16. 191.32.6.21 is a class ____ address.
Matching
Match the Address or Subnet to
its class.
|
a. |
Class A |
e. |
Class E |
|
b. |
Class B |
f. |
Broadcast |
|
c. |
Class C |
g. |
Default Network |
|
d. |
Class D |
h. |
Loopback |
____ 17. 127.0.0.1
____ 18. Reserved for multicasts
____ 19. 15.26.85.56
____ 20. 193.5.224.34
____ 21. 45.85.169.22
____ 22. Experimental address group
____ 23. 0.0.0.0
____ 24. 255.255.255.255
____ 25. 255.0.0.0 is the default subnet mask for this
class of addresses
____ 26. 255.255.255.0 is the default subnet mask for
this class of addresses
____ 27. 255.255.0.0 is the default subnet mask for
this class of addresses
____ 28. 122.56.45.251
____ 29. 220.25.35.1
____ 30. 191.168.2.3
Binary
Practice Problems
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128 |
64 |
32 |
16 |
8 |
4 |
2 |
1 |
Decimal Number |
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0 |
1 |
1 |
1 |
0 |
0 |
1 |
0 |
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1 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
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1 |
1 |
1 |
1 |
1 |
1 |
1 |
0 |
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1 |
1 |
1 |
1 |
1 |
1 |
1 |
1 |
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0 |
1 |
0 |
0 |
0 |
0 |
1 |
0 |
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0 |
0 |
0 |
1 |
0 |
0 |
0 |
1 |
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1 |
1 |
1 |
0 |
0 |
1 |
0 |
1 |
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1 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
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1 |
1 |
1 |
0 |
0 |
0 |
0 |
0 |
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1 |
1 |
1 |
1 |
0 |
0 |
0 |
0 |
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128 |
64 |
32 |
16 |
8 |
4 |
2 |
1 |
Decimal Number |
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248 |
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123 |
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7 |
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22 |
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169 |
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252 |
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224 |
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99 |
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224 |
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255 |
Subnetting
Specify
The Correct Default Subnet Mask for the Following Addresses:
Review: Default Subnet Masks
Recommended Process
Determine address class of address.
Determine appropriate default subnet mask.
|
IP Address |
Class |
Default subnet mask |
|
210.51.67.102 |
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67.23.148.0 |
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158.78.251.33 |
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145.23.117.241 |
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192.200.23.5 |
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144.225.78.1 |
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63.78.14.211 |
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192.35.128.36 |
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Determine the Custom Subnet Masks
Example Scenario
|
Required # of physical segments |
3 |
|
Max # of hosts per segment |
4000 |
|
Network address |
142.25.0.0 |
|
Default subnet mask |
255.255.0.0 |
|
Proposed custom subnet mask |
255.255.224.0 |
|
Number of subnets supported |
6 |
|
Maximum number of host IDs per subnet |
8190 |
Scenario One
|
Required # of physical segments |
12 |
|
Max # of hosts per segment |
500 |
|
Network address |
191.32.0.0 |
|
Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Scenario Two
|
Required # of physical segments |
12 |
|
Max # of hosts per segment |
12 |
|
Network address |
195.15.12.0 |
|
Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Scenario Three
|
Required # of physical segments |
1000 |
|
Max # of hosts per segment |
12000 |
|
Network address |
12.0.0.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Scenario Four
|
Required # of physical segments |
28 |
|
Max # of hosts per segment |
1500 |
|
Network address |
130.15.0.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Scenario Five
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Required # of physical segments |
2 |
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Max # of hosts per segment |
60 |
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Network address |
199.32.18.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Determine
Subnet IDs and Ranges of Host IDs
Example
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Required # of
physical segments |
3 |
|
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Max # of hosts per
segment |
4000 |
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Network address |
142.25.0.0 |
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Default subnet mask |
255.255.0.0 |
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Proposed custom
subnet mask |
255.255.224.0 |
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Number of subnets
supported |
6 |
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Maximum number of
host IDs per subnet |
8190 |
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Subnet IDs (don’t
include the invalid subnets) |
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||
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142.25.32.0 142.25.64.0 142.25.96.0 142.25.128.0 142.25.160.0 142.25.192.0 |
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||
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Host ID Ranges Per
Subnet |
Network Address |
1st Host |
Last Host on subnet |
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142.25.32.0 |
142.25.32.1 |
142.25.32.0 |
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142.25.64.0 |
142.25.64.1 |
142.25.95.254 |
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142.25.96.0 |
142.25.96.1 |
142.25.127.254 |
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142.25.128.0 |
142.25.128.1 |
142.25.159.254 |
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142.25.160.0 |
142.25.160.1 |
142.25.191.254 |
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142.25.192.0 |
142.25.192.1 |
142.25.223.254 |
Scenario One
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Required # of physical segments |
12 |
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Max # of hosts per segment |
500 |
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Network address |
191.32.0.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Subnet IDs (don’t include the invalid subnets) |
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Host ID Ranges Per Subnet |
Network Address |
1st Host |
Last Host on subnet |
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Scenario Two
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Required # of physical segments |
12 |
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Max # of hosts per segment |
12 |
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Network address |
195.15.12.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Subnet IDs (don’t include the invalid subnets) |
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Host ID Ranges Per Subnet |
Network Address |
1st Host |
Last Host on subnet |
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Scenario Three
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Required # of physical segments |
1000 |
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Max # of hosts per segment |
12000 |
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Network address |
12.0.0.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Naw…I
won’t make you do this one. That would be evil.
Scenario Four
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Required # of physical segments |
6 |
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Max # of hosts per segment |
8000 |
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Network address |
130.15.0.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Subnet IDs (don’t include the invalid subnets) |
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Host ID Ranges Per Subnet |
Network Address |
1st Host |
Last Host on subnet |
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Scenario Five
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Required # of physical segments |
2 |
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Max # of hosts per segment |
60 |
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Network address |
199.32.18.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Subnet IDs (don’t include the invalid subnets) |
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Host ID Ranges Per Subnet |
Network Address |
1st Host |
Last Host on subnet |
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Networking Labs
Job One: Converting Binary Numbers to Decimal Numbers Using Windows Calculator
|
Decimal |
Binary |
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10 |
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|
158 |
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254 |
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32 |
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33 |
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Binary |
Decimal |
|
00101 |
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1110010 |
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101010 |
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11111110 |
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00000011 |
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Job Two: Defining a Subnet for Your Network
|
Network Address |
1st Host ID |
Last Host ID |
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Job Three: IP Subnet Calculator
|
Required # of physical segments |
5 |
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Max # of hosts per segment |
32 |
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Network address |
126.0.0.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Network Address |
1st Host address |
Last Host Address |
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Required # of physical segments |
2 |
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Max # of hosts per segment |
62 |
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Network address |
198.26.222.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Network Address |
1st Host address |
Last Host Address |
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Required # of physical segments |
2 |
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Max # of hosts per segment |
62 |
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Network address |
129.33.0.0 |
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Default subnet mask |
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Proposed custom subnet mask |
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Number of subnets supported |
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Maximum number of host IDs per subnet |
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Network Address |
1st Host address |
Last Host Address |
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